You wish to construct a 90% confidence interval to compare two proportions.If we wish to obtain a margin of error of at most 0.03,what sample size should we take from each group? Assume equal sample sizes.

A) 752
B) 1504
C) 1503
D) 751
E) 1984

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Fikile Mathye · Accepted Answer

Final Answer : B, Explanation :  To calculate the sample size for a given margin of error in a confidence interval for two proportions, we use the formula: n = (Z^2 * (p1(1-p1) + p2(1-p2))) / E^2. For a 90% confidence interval, Z is approximately 1.645. Assuming p1 and p2 are both 0.5 (worst-case scenario for maximum variability), and E is 0.03, the calculation gives a sample size of approximately 1504 for each group.

You wish to construct a 90% confidence interval to compare two proportions.If we wish to obtain a margin of error of at most 0.03,what sample size should we take from each group? Assume equal sample sizes.

A) 752
B) 1504
C) 1503
D) 751
E) 1984

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You wish to construct a 90% confidence interval to compare two proportions.If we wish to obtain a margin of error of at most 0.03,what sample size should we take from each group? Assume equal sample sizes.A) 752B) 1504C) 1503D) 751E) 1984

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Learning Objectives

Learning Objectives

Related questions

You wish to construct a 90% confidence interval to compare two proportions.If we wish to obtain a margin of error of at most 0.03,what sample size should we take from each group? Assume equal sample sizes.

A) 752
B) 1504
C) 1503
D) 751
E) 1984