In a series RL circuit, E T = 120 V, R = 30 Ω , and X L = 40 Ω . What is the apparent power?A) 17.92 VAB) 172.8 VAC) 230.4 VAD) 288 VA

Question

In a series RL circuit, E T  = 120 V, R = 30 Ω , and X L  = 40 Ω . What is the apparent power?A)  17.92 VAB)  172.8 VAC)  230.4 VAD)  288 VA

Stephan Hampton · Accepted Answer

Final Answer : D, Explanation :  The apparent power (S) in a series RL circuit is calculated using the formula S = E T  * I, where I is the current. First, calculate the impedance Z = √(R² + X L ²) = √(30² + 40²) = 50 Ω. Then, the current I = E T  / Z = 120 V / 50 Ω = 2.4 A. Finally, the apparent power S = 120 V * 2.4 A = 288 VA.

In a series RL circuit, E_T = 120 V, R = 30 Ω , and X_L = 40 Ω . What is the apparent power?

A) 17.92 VA
B) 172.8 VA
C) 230.4 VA
D) 288 VA

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Learning Objectives

Related questions

In a series RL circuit, ET = 120 V, R = 30 Ω , and XL = 40 Ω . What is the apparent power?A) 17.92 VAB) 172.8 VAC) 230.4 VAD) 288 VA

Definitions

Learning Objectives

Learning Objectives

Related questions

In a series RL circuit, E_T = 120 V, R = 30 Ω , and X_L = 40 Ω . What is the apparent power?

A) 17.92 VA
B) 172.8 VA
C) 230.4 VA
D) 288 VA