Consider a game that consists of dealing out a hand of two random cards from a deck of four cards.The deck contains the Ace of Spades (As) ,the Ace of Hearts (Ah) ,the King of Spades (Ks) and the 9 of Hearts (9h) .What is the probability that you have at least one Ace?

A) 1/6
B) 2/6
C) 3/6
D) 4/6
E) 5/6

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Mirai Kuriyama · Accepted Answer

Final Answer : E, Explanation :  To calculate the probability of having at least one Ace in a hand of two cards drawn from a deck of four cards (Ace of Spades, Ace of Hearts, King of Spades, and 9 of Hearts), we can use the complement rule. The complement of having at least one Ace is having no Aces at all. There are 2 ways to draw a hand with no Aces (Ks9h), out of a total of 6 possible hands (since there are 4 cards and we are choosing 2, the total number of combinations is 4C2 = 6). Therefore, the probability of not having an Ace is 2/6, and the probability of having at least one Ace is 1 - 2/6 = 4/6 or 5/6.

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Consider a game that consists of dealing out a hand of two random cards from a deck of four cards.The deck contains the Ace of Spades (As) ,the Ace of Hearts (Ah) ,the King of Spades (Ks) and the 9 of Hearts (9h) .What is the probability that you have at least one Ace?A) 1/6B) 2/6C) 3/6D) 4/6E) 5/6

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