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Dr.Disney has been raising exotic fruit flies for decades.Recently, he discovered a strain of fruit flies that in the recessive condition have baby blue eyes that he designates as bb.He also has another strain of fruit flies that in the recessive condition have pink wings that are designated as pw.He is able to establish flies that are homozygous for both mutant traits.He mates these two strains with each other.Dr.Disney then takes phenotypically wild-type females from this cross and mates them with double recessive males.In the resulting testcross progeny, he observes 500 flies that are of the following make-up: Dr.Disney has been raising exotic fruit flies for decades.Recently, he discovered a strain of fruit flies that in the recessive condition have baby blue eyes that he designates as bb.He also has another strain of fruit flies that in the recessive condition have pink wings that are designated as pw.He is able to establish flies that are homozygous for both mutant traits.He mates these two strains with each other.Dr.Disney then takes phenotypically wild-type females from this cross and mates them with double recessive males.In the resulting testcross progeny, he observes 500 flies that are of the following make-up:   Assuming the wild-type alleles for these two genes are b+ and pw+, what is the CORRECT testcross of the F<sub>1</sub> flies? A) bb<sup>+</sup> pw<sup>+</sup>/bb pw × bb pw/bb pw B) bb<sup>+</sup> pw<sup>+</sup>/bb pw × bb pw<sup>+</sup>/bb<sup>+ </sup>pw C) bb<sup>+ </sup>pw/bb pw<sup>+</sup> × bb pw/bb pw D) bb<sup>+</sup> pw/bb pw<sup>+</sup> × bb<sup>+</sup> pw<sup>+</sup>/bb pw E) bb<sup>+</sup> pw<sup>+</sup>/bb pw × bb<sup>+</sup> pw/bb pw<sup>+</sup> Assuming the wild-type alleles for these two genes are b+ and pw+, what is the CORRECT testcross of the F1 flies?


A) bb+ pw+/bb pw × bb pw/bb pw
B) bb+ pw+/bb pw × bb pw+/bb+ pw
C) bb+ pw/bb pw+ × bb pw/bb pw
D) bb+ pw/bb pw+ × bb+ pw+/bb pw
E) bb+ pw+/bb pw × bb+ pw/bb pw+

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Three-factor testcrosses are only informative in gene mapping when which of the following occurs?


A) One parent is homozygous recessive for the three genes, and the other parent is homozygous dominant.
B) All three genes are located on separate chromosomes, and one parent is homozygous dominant for at least two of these genes.
C) Both parents are homozygous for the three genes.
D) One parent is heterozygous for the three genes, and the other parent is homozygous recessive.
E) One of the genes must be located on a sex chromosome and be heterozygous, and the other two genes must be located on an autosome and be homozygous.

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Linked genes always exhibit:


A) phenotypes that are similar.
B) recombination frequencies of less than 50%.
C) homozygosity when involved in a testcross.
D) a greater number of recombinant offspring than parental offspring when involved in a testcross.
E) a lack of recombinant offspring when a heterozygous parent is testcrossed.

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In flower beetles, pygmy (py) is recessive to normal size (py+) , and red color (r) is recessive to brown (r+) .A beetle heterozygous for these characteristics was test crossed to a beetle homozygous for pygmy and red.The following are progeny phenotypes from this testcross: In flower beetles, pygmy (py) is recessive to normal size (py<sup>+</sup>) , and red color (r) is recessive to brown (r<sup>+</sup>) .A beetle heterozygous for these characteristics was test crossed to a beetle homozygous for pygmy and red.The following are progeny phenotypes from this testcross:   Carry out a series of chi-square tests to determine if there is equal segregation of alleles at the py locus.What is the CORRECT chi-square value and how many degree(s) of freedom should be used in its interpretation? A) 0) 16 with one degree of freedom B) 0) 16 with three degrees of freedom C) 0) 48 with one degree of freedom D) 0) 48 with two degrees of freedom E) 4) 56 with one degree of freedom Carry out a series of chi-square tests to determine if there is equal segregation of alleles at the py locus.What is the CORRECT chi-square value and how many degree(s) of freedom should be used in its interpretation?


A) 0) 16 with one degree of freedom
B) 0) 16 with three degrees of freedom
C) 0) 48 with one degree of freedom
D) 0) 48 with two degrees of freedom
E) 4) 56 with one degree of freedom

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Forensic biologist use well defined Y chromosomal markers to analyze case evidence.If there were five markers on the Y chromosome, each with five different alleles, how do you predict these would be inherited across men involved in criminal investigations?

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The various Y chromosomes markers would ...

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A linkage group:


A) involves on or more genes found on different chromosomes.
B) is when two genes interact with each other to form a phenotype.
C) is formed between one or more genes residing close together on a chromosome.
D) involves genetic recombination of greater than 50% among two genes.
E) is when one gene effects the expression of another gene.

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You are doing lab work with a new species of beetle.You isolated lines that breed true for either blue shells and long antenna, or green shells and short antenna.Crossing these lines yields F1 progeny with blue shells and long antenna.Crossing F1 progeny with beetles that have green shells and short antenna yield the following progeny: You are doing lab work with a new species of beetle.You isolated lines that breed true for either blue shells and long antenna, or green shells and short antenna.Crossing these lines yields F<sub>1</sub> progeny with blue shells and long antenna.Crossing F<sub>1</sub> progeny with beetles that have green shells and short antenna yield the following progeny:   A chi-square test is done to test for independent assortment.What is the resulting chi-square value and how many degree(s) of freedom should be used in its interpretation? A) 27.1 and one degree of freedom B) 14.9 and three degrees of freedom C) 14.9 and two degrees of freedom D) 27.1 and three degrees of freedom E) 0) 42 and two degrees of freedom A chi-square test is done to test for independent assortment.What is the resulting chi-square value and how many degree(s) of freedom should be used in its interpretation?


A) 27.1 and one degree of freedom
B) 14.9 and three degrees of freedom
C) 14.9 and two degrees of freedom
D) 27.1 and three degrees of freedom
E) 0) 42 and two degrees of freedom

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Recombination frequencies can be calculated by:


A) counting the number of recombinant and parental offspring when an individual who is heterozygous for two genes is testcrossed.
B) performing a chi-square test on the F2 progeny when an individual who is homozygous for two genes is initially crossed to an individual who is homozygous recessive for these two genes.
C) counting the number of offspring who are expressing the dominant phenotype when a heterozygous individual for two genes is testcrossed.
D) performing a chi-square test of the progeny of a cross between parents who are both heterozygous for the same two genes.
E) counting the number of offspring that are found in the cross of an individual who is heterozygous for two genes with another parent who is homozygous dominant for one of these genes and homozygous recessive for the other gene.

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You just bought two black guinea pigs, one male and one female, of the same genotype from the pet store that are known to be heterozygous (Bb) .You also know that black fur (BB) is dominant over white fur (bb) and that a lethal recessive allele is located only one cM away from the recessive b allele, and your animals are both heterozygous for this gene also.What is the probability of finding a white individual among the progeny if you cross these two animals?


A) 0) 25
B) 0) 002475
C) 0) 000025
D) 0) 004975
E) 0) 495

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Two linked genes, (A) and (B) , are separated by 18 cM.A man with genotype Aa Bb marries a woman who is aa bb.The man's father was AA BB.What is the probability that their first two children will both be ab/ab?


A) 0) 168
B) 0) 0081
C) 0) 032
D) 0) 062
E) 0) 13

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Interference occurs when:


A) two genes are assorting independently.
B) two genes are far apart on a genetic map.
C) one crossover inhibits another.
D) the number recombinant progeny classes in the testcross of a heterozygote exceeds the number of parental progeny.
E) a crossover causes the termination of the meiosis event in which the crossover is occurring.

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The map distances for genes that are close to each other are more accurate than map distances for genes that are quite far apart because:


A) with genes that are far apart, double crossover and other multiple crossover events often lead to lethal recombinants that reduce the number of recombinant progeny.
B) with genes that are far apart, double crossover and other multiple crossover events often lead to nonrecombinant or parental offspring and thus reduce the true map distance.
C) crossover interference will cause more double crossover and other multiple crossover events to occur than would be expected and thus result in a higher number of recombinant progeny than expected to occur with genes that are far apart.
D) double crossover and other multiple crossover events occur more often when genes are close to each other and can be readily detected, so these map distances are more accurate than those for genes that are far apart.
E) when genes are far apart, single crossover recombinant classes are more difficult to detect than when genes are close together.

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A testcross includes:


A) one parent who is homozygous recessive for one gene pair and a second parent who is homozygous recessive for a second gene pair.
B) one parent who is homozygous dominant for one or more genes and a second parent who is homozygous recessive for these same genes.
C) two parents who are both heterozygous for two or more genes.
D) one parent who shows the dominant phenotype for one or more genes and a second parent who is homozygous recessive for these genes.
E) one parent who shows the recessive phenotype for one or more genes and a second parent who is homozygous dominant for these genes.

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What is the CORRECT gene order? What is the CORRECT gene order?   A) A b D B) a B D C) A D B D) a d b E) B a d


A) A b D
B) a B D
C) A D B
D) a d b
E) B a d

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Recombination occurs through:


A) crossing over and chromosome interference.
B) chromosome interference and independent assortment.
C) somatic-cell hybridization and chromosome interference.
D) complete linkage and chromosome interference.
E) crossing over and independent assortment.

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A genome-wide association study helps identify genetic traits by:


A) independent assortment association.
B) linkage of genetic traits to haplotypes within a population.
C) analysis of single nucleotide polymorphisms.
D) likelihood of linkage between genes on different chromosomes.
E) linkage disequilibrium among other genes.

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What is the map distance between the A and B genes? What is the map distance between the A and B genes?   A) 1 cM B) 5 cM C) 10 cM D) 12 cM E) 20 cM


A) 1 cM
B) 5 cM
C) 10 cM
D) 12 cM
E) 20 cM

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You are studying two linked genes in lizards.You have two females and you know that both are the same genotype, heterozygous for both genes (A/a and B/b) .You test-cross each female to a male that is fully homozygous recessive for both genes (a/a and b/b) and get the following progeny with the following phenotypes: You are studying two linked genes in lizards.You have two females and you know that both are the same genotype, heterozygous for both genes (A/a and B/b) .You test-cross each female to a male that is fully homozygous recessive for both genes (a/a and b/b) and get the following progeny with the following phenotypes:   How can you explain the drastic difference between these two crosses? A) The two genes are assorting independently in female 1 and are linked in female 2. B) The two genes are linked in female 1 and are assorting independently in female 2. C) The two alleles are in the coupling configuration in female 1 but in the repulsion configuration in female 2. D) The two alleles are in the repulsion configuration in female 1 but in the coupling configuration in female 2. E) The two genes are likely located on a sex chromosome in female 1 and are likely located on an autosome in female 2. How can you explain the drastic difference between these two crosses?


A) The two genes are assorting independently in female 1 and are linked in female 2.
B) The two genes are linked in female 1 and are assorting independently in female 2.
C) The two alleles are in the coupling configuration in female 1 but in the repulsion configuration in female 2.
D) The two alleles are in the repulsion configuration in female 1 but in the coupling configuration in female 2.
E) The two genes are likely located on a sex chromosome in female 1 and are likely located on an autosome in female 2.

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A situation where the coefficient of coincidence is greater than 1.0 would indicate that:


A) the interference is high and one crossover suppresses the occurrence of a second one.
B) no double crossovers were found in the progeny of a testcross, even though some were expected based on probability.
C) double crossovers were found in the progeny of a testcross, but there were fewer of them than would be expected based on probability.
D) there were more double crossovers in the progeny than would be expected based on probability.
E) the genes involved were actually assorting independently.

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The results of linkage analysis for DNA marker A and the p53 gene are shown below.What is the best estimate for the approximate genetic distance between marker A and the p53 gene in humans? The results of linkage analysis for DNA marker A and the p53 gene are shown below.What is the best estimate for the approximate genetic distance between marker A and the p53 gene in humans?   A) 1 cM B) 5 cM C) 10 cM D) 20 cM E) 30 cM


A) 1 cM
B) 5 cM
C) 10 cM
D) 20 cM
E) 30 cM

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