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For comparing two or more populations each having two or more categories, you can use which test(s)?

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You can use a chi-sq...

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The chi-squared test of a(n) ____________________ is used to determine whether there is enough evidence to say two nominal variables are related.

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Suppose that a random sample of 60 observations was drawn from a population.After calculating the mean and standard deviation, each observation was standardized and the number of observations in each of the intervals below was counted.Can we infer at the 10% significance level that the data were drawn from a normal population? Suppose that a random sample of 60 observations was drawn from a population.After calculating the mean and standard deviation, each observation was standardized and the number of observations in each of the intervals below was counted.Can we infer at the 10% significance level that the data were drawn from a normal population?

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H0: p1 = .1587, p2 = .3413, p3 = .3413, p4 = ...

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If we square the value of z (the test statistic in the test of a proportion) we produce the ____________________ statistic.

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chi-square...

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If we use theIf we use the  goodness-of-fit to test for the differences among 4 proportions, the degrees of freedom is equal to: A)  3 B)  4 C)  5 D)  None of these choices. goodness-of-fit to test for the differences among 4 proportions, the degrees of freedom is equal to:


A) 3
B) 4
C) 5
D) None of these choices.

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Seat Belts A study was conducted to determine whether the use of seat belts in vehicles depends on whether or not a child was present in the car.A sample of 1,000 people treated for injuries sustained from vehicle accidents was obtained, and each person was classified according to (1) child present (yes/no) and (2) seat belt usage (worn or not worn) during the accident.The data are shown in the table below. Seat Belts A study was conducted to determine whether the use of seat belts in vehicles depends on whether or not a child was present in the car.A sample of 1,000 people treated for injuries sustained from vehicle accidents was obtained, and each person was classified according to (1) child present (yes/no) and (2) seat belt usage (worn or not worn) during the accident.The data are shown in the table below.    -{Seat Belts Narrative} Calculate the value of the test statistic. -{Seat Belts Narrative} Calculate the value of the test statistic.

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The alternative hypothesis in a goodness-of-fit test is that none of the pi values are equal to their values specified in H0.

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A small chi-squared test statistic in a goodness-of-fit test supports the null hypothesis.

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In a goodness-of-fit test, the null hypothesis states that the data came from a normally distributed population.The researcher estimated the population mean and population standard deviation from a sample of 500 observations.In addition, the researcher used 6 standardized intervals to test for normality.Using a 5% level of significance, the critical value for this test is:


A) 11.1433
B) 9.3484
C) 7.8147
D) 9.4877

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A test for the differences between two proportions can be performed using the chi-squared distribution.

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How do you find the probabilities needed to obtain expected frequencies for a test of a contingency table?


A) If there are r rows and c columns, let each probability be 1/rc.
B) Use the probabilities specified in the null hypothesis.
C) Assume H0 is true and use your data to calculate them.
D) None of these choices.

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Which of the following tests does not use the chi-squared distribution?


A) Test of a contingency table.
B) Goodness-of-fit test.
C) One tailed test for two proportions.
D) None of these choices.

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In a goodness-of-fit test, H0 lists specific values for proportions and the test of a contingency table does not.

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Suppose the value of your chi-squared test statistic in a goodness-of-fit test is equal to 0.What do you conclude?


A) Reject H0.Conclude that at least one proportion is not equal to its specified value.
B) Fail to reject H0.Not enough evidence to say the proportions are different from what is listed in H0.
C) Not enough information; need the degrees of freedom for the test.
D) None of these choices.

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There are two critical factors in identifying the technique used when the data are nominal.The first is the problem objective.The second is the number of ____________________ that nominal variable can assume.

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A chi-squared distribution is symmetric.

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Consider a multinomial experiment involving 100 trials and 3 categories (cells).The observed frequencies resulting from the experiment are shown in the accompanying table. Consider a multinomial experiment involving 100 trials and 3 categories (cells).The observed frequencies resulting from the experiment are shown in the accompanying table.     Use the 5% significance level to test the hypotheses H<sub>0</sub>: p<sub>1</sub> = .45, p<sub>2</sub> = .30, p<sub>3</sub> = .25 vs.H<sub>1</sub>: At least one proportion differs from their specified values. Use the 5% significance level to test the hypotheses H0: p1 = .45, p2 = .30, p3 = .25 vs.H1: At least one proportion differs from their specified values.

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Rejection region: blured image> blured image.05,2 = 5.991
...

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A chi-squared distribution has a shape that is ____________________.

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positively...

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Which of the following represents H1 in a chi-squared goodness-of-fit test to see if all 5 colors of a certain candy appear in the same proportion in the population?


A) H1: p1 = p2 = p3 = p4 = p5 = .20.
B) H1: At least one proportion is not equal to .20.
C) H1: None of these proportions are equal.
D) None of these choices.

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Which of the following tests is appropriate for nominal data if the problem objective is to compare two populations and the number of categories exceeds 2?


A) The z-test for one proportion, p, or difference of two proportions, p1 - p2.
B) The chi-squared goodness-of-fit test.
C) The chi-squared test of a contingency table.
D) All of these choices are true.

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