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A thin, circular disk of radius 30.0 cm is oriented in the yz-plane with its center at the origin. The disk carries a total charge of +3.00 μC distributed uniformly over its surface. Calculate the magnitude of the electric field due to the disk at the point x = 15.0 cm along the x-axis. (ε0 = 8.85 × 10-12 C2/N ∙ m2)


A) 9.95 × 105 N/C
B) 4.98 × 105 N/C
C) 3.31 × 105 N/C
D) 2.49 × 105 N/C
E) 1.99 × 105 N/C

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A dipole with a positive charge of A dipole with a positive charge of   and a negative charge of   is centered at the origin and oriented along the x-axis with the positive charge located to the right of the origin. The charge separation is 0.0010 m. Find the electric field due to this dipole at the point     (k = 1/4πε<sub>0</sub> = 8.99 × 10<sup>9</sup> N ∙ m<sup>2</sup>/C<sup>2</sup>)  A)  0.56   N/C B)  -0.56   N/C C)  0.28   N/C D)  -0.28   N/C and a negative charge of A dipole with a positive charge of   and a negative charge of   is centered at the origin and oriented along the x-axis with the positive charge located to the right of the origin. The charge separation is 0.0010 m. Find the electric field due to this dipole at the point     (k = 1/4πε<sub>0</sub> = 8.99 × 10<sup>9</sup> N ∙ m<sup>2</sup>/C<sup>2</sup>)  A)  0.56   N/C B)  -0.56   N/C C)  0.28   N/C D)  -0.28   N/C is centered at the origin and oriented along the x-axis with the positive charge located to the right of the origin. The charge separation is 0.0010 m. Find the electric field due to this dipole at the point A dipole with a positive charge of   and a negative charge of   is centered at the origin and oriented along the x-axis with the positive charge located to the right of the origin. The charge separation is 0.0010 m. Find the electric field due to this dipole at the point     (k = 1/4πε<sub>0</sub> = 8.99 × 10<sup>9</sup> N ∙ m<sup>2</sup>/C<sup>2</sup>)  A)  0.56   N/C B)  -0.56   N/C C)  0.28   N/C D)  -0.28   N/C A dipole with a positive charge of   and a negative charge of   is centered at the origin and oriented along the x-axis with the positive charge located to the right of the origin. The charge separation is 0.0010 m. Find the electric field due to this dipole at the point     (k = 1/4πε<sub>0</sub> = 8.99 × 10<sup>9</sup> N ∙ m<sup>2</sup>/C<sup>2</sup>)  A)  0.56   N/C B)  -0.56   N/C C)  0.28   N/C D)  -0.28   N/C (k = 1/4πε0 = 8.99 × 109 N ∙ m2/C2)


A) 0.56 A dipole with a positive charge of   and a negative charge of   is centered at the origin and oriented along the x-axis with the positive charge located to the right of the origin. The charge separation is 0.0010 m. Find the electric field due to this dipole at the point     (k = 1/4πε<sub>0</sub> = 8.99 × 10<sup>9</sup> N ∙ m<sup>2</sup>/C<sup>2</sup>)  A)  0.56   N/C B)  -0.56   N/C C)  0.28   N/C D)  -0.28   N/C N/C
B) -0.56 A dipole with a positive charge of   and a negative charge of   is centered at the origin and oriented along the x-axis with the positive charge located to the right of the origin. The charge separation is 0.0010 m. Find the electric field due to this dipole at the point     (k = 1/4πε<sub>0</sub> = 8.99 × 10<sup>9</sup> N ∙ m<sup>2</sup>/C<sup>2</sup>)  A)  0.56   N/C B)  -0.56   N/C C)  0.28   N/C D)  -0.28   N/C N/C
C) 0.28 A dipole with a positive charge of   and a negative charge of   is centered at the origin and oriented along the x-axis with the positive charge located to the right of the origin. The charge separation is 0.0010 m. Find the electric field due to this dipole at the point     (k = 1/4πε<sub>0</sub> = 8.99 × 10<sup>9</sup> N ∙ m<sup>2</sup>/C<sup>2</sup>)  A)  0.56   N/C B)  -0.56   N/C C)  0.28   N/C D)  -0.28   N/C N/C
D) -0.28 A dipole with a positive charge of   and a negative charge of   is centered at the origin and oriented along the x-axis with the positive charge located to the right of the origin. The charge separation is 0.0010 m. Find the electric field due to this dipole at the point     (k = 1/4πε<sub>0</sub> = 8.99 × 10<sup>9</sup> N ∙ m<sup>2</sup>/C<sup>2</sup>)  A)  0.56   N/C B)  -0.56   N/C C)  0.28   N/C D)  -0.28   N/C N/C

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Two flat 4.0 cm × 4.0 cm electrodes carrying equal but opposite charges are spaced 2.0 mm apart with their midpoints opposite each other. Between the electrodes but not near their edges, the electric field strength is 2.5 × 106 N/C. What is the magnitude of the charge on each electrode? (ε0 = 8.85 × 10-12 C2/N ∙ m2)


A) 35 nC
B) 18 nC
C) 16 nC
D) 30 nC

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Two point charges Q1 and Q2 of equal magnitudes and opposite signs are positioned as shown in the figure. Which of the arrows best represents the net electric field at point P due to these two charges? Two point charges Q<sub>1</sub> and Q<sub>2</sub> of equal magnitudes and opposite signs are positioned as shown in the figure. Which of the arrows best represents the net electric field at point P due to these two charges?   A)  A B)  B C)  C D)  D E)  The field is equal to zero at point P.


A) A
B) B
C) C
D) D
E) The field is equal to zero at point P.

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An electric field is set up between two parallel plates, each of area 2.0 m2, by putting 1.0 μC of charge on one plate and -1.0 μC of charge on the other. The plates are separated by 4.0 mm with their centers opposite each other, and the charges are distributed uniformly over the surface of the plates. What is the magnitude of the electric field between the plates at a distance of 1.0 mm from the positive plate, but not near the edges of the plates? (ε0 = 8.85 × 10-12 C2/N ∙ m2)


A) 4.2 × 104 N/C
B) 1.4 × 104 N/C
C) 3.1 × 104 N/C
D) 0.00 N/C
E) 5.6 × 104 N/C

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Three +3.0-μC point charges are at the three corners of a square of side 0.50 m. The last corner is occupied by a -3.0-μC charge. Find the magnitude of the electric field at the center of the square. (k = 1/4πε0 = 8.99 × 109 N ∙ m2/C2)

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A pair of charged conducting plates produces a uniform field of 12,000 N/C, directed to the right, between the plates. The separation of the plates is 40 mm. An electron is projected from plate A, directly toward plate B, with an initial velocity of vo = 1.0 × 107 m/s, as shown in the figure. (e = 1.60 × 10-19 C, ε0 = 8.85 × 10-12 C2/N ∙ m2, mel = 9.11 × 10-31 kg) The distance of closest approach of the electron to plate B is nearest to A pair of charged conducting plates produces a uniform field of 12,000 N/C, directed to the right, between the plates. The separation of the plates is 40 mm. An electron is projected from plate A, directly toward plate B, with an initial velocity of v<sub>o</sub> = 1.0 × 10<sup>7 </sup>m/s, as shown in the figure. (e<sub> </sub>= 1.60 × 10<sup>-19 </sup>C, ε<sub>0</sub> = 8.85 × 10<sup>-12</sup> C<sup>2</sup>/N ∙ m<sup>2</sup>, m<sub>el</sub> = 9.11 × 10<sup>-31</sup> kg)  The distance of closest approach of the electron to plate B is nearest to   A)  16 mm. B)  18 mm. C)  20 mm. D)  22 mm. E)  24 mm.


A) 16 mm.
B) 18 mm.
C) 20 mm.
D) 22 mm.
E) 24 mm.

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Two thin 80.0-cm rods are oriented at right angles to each other. Each rod has one end at the origin of the coordinates, and one of them extends along the +x-axis while the other extends along the +y-axis. The rod along the +x-axis carries a charge of -15.0 µC distributed uniformly along its length, and the other rod carries +15.0 µC uniformly over its length. Find the magnitude and direction of the net electrical force that these two rods exert on an electron located at the point (40.0 cm, 40.0 cm). (e = 1.60 × 10-19 C, ε0 = 8.85 × 10-12 C2/N ∙ m2)

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1.35 × 10-13 ...

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In the figure, a ring 0.71 m in radius carries a charge of + 580 nC uniformly distributed over it. A point charge Q is placed at the center of the ring. The electric field is equal to zero at field point P, which is on the axis of the ring, and 0.73 m from its center. (ε0 = 8.85 × 10-12 C2/N ∙ m2) The point charge Q is closest to In the figure, a ring 0.71 m in radius carries a charge of + 580 nC uniformly distributed over it. A point charge Q is placed at the center of the ring. The electric field is equal to zero at field point P, which is on the axis of the ring, and 0.73 m from its center. (ε<sub>0</sub> = 8.85 × 10<sup>-12</sup> C<sup>2</sup>/N ∙ m<sup>2</sup>)  The point charge Q is closest to   A)  -210. B)  -300. C)  -420. D)  210. E)  300.


A) -210.
B) -300.
C) -420.
D) 210.
E) 300.

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An electric dipole is made of two charges of equal magnitudes and opposite signs. The positive charge, q = 1.0 μC, is located at the point (x, y, z) = (0.00 cm, 1.0 cm, 0.00 cm) , while the negative charge is located at the point (x, y, z) = (0.00 cm, -1.0 cm, 0.00 cm) . How much work will be done by an electric field An electric dipole is made of two charges of equal magnitudes and opposite signs. The positive charge, q = 1.0 μC, is located at the point (x, y, z)  = (0.00 cm, 1.0 cm, 0.00 cm) , while the negative charge is located at the point (x, y, z)  = (0.00 cm, -1.0 cm, 0.00 cm) . How much work will be done by an electric field   = (3.0 × 10<sup>6</sup> N/C)    to bring the dipole to its stable equilibrium position? A)  0.060 J B)  0.030 J C)  0.00 J D)  0.020 J E)  0.12 J = (3.0 × 106 N/C) An electric dipole is made of two charges of equal magnitudes and opposite signs. The positive charge, q = 1.0 μC, is located at the point (x, y, z)  = (0.00 cm, 1.0 cm, 0.00 cm) , while the negative charge is located at the point (x, y, z)  = (0.00 cm, -1.0 cm, 0.00 cm) . How much work will be done by an electric field   = (3.0 × 10<sup>6</sup> N/C)    to bring the dipole to its stable equilibrium position? A)  0.060 J B)  0.030 J C)  0.00 J D)  0.020 J E)  0.12 J to bring the dipole to its stable equilibrium position?


A) 0.060 J
B) 0.030 J
C) 0.00 J
D) 0.020 J
E) 0.12 J

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A point charge Q = -500 nC and two unknown point charges, q1 and q2, are placed as shown in the figure. The electric field at the origin O, due to charges Q, q1 and q2, is equal to zero. The charge q1 is closest to A point charge Q = -500 nC and two unknown point charges, q<sub>1</sub> and q<sub>2</sub>, are placed as shown in the figure. The electric field at the origin O, due to charges Q, q<sub>1</sub> and q<sub>2</sub>, is equal to zero. The charge q<sub>1</sub> is closest to   A)  130 nC. B)  76 nC. C)  150 nC. D)  -76 nC. E)  -130 nC.


A) 130 nC.
B) 76 nC.
C) 150 nC.
D) -76 nC.
E) -130 nC.

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The electric field strength in the space between two closely spaced parallel disks is .0 × 105 N/C. This field is the result of transferring 3.9 × 109 electrons from one disk to the other. What is the diameter of the disks? (e = 1.60 × 10-19 C, ε0 = 8.85 × 10-12 C2/N ∙ m2)


A) 3.0 cm
B) 1.5 cm
C) 4.5 cm
D) 6.0 cm

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